5y^2+4y+12=0

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Solution for 5y^2+4y+12=0 equation:


Simplifying
5y2 + 4y + 12 = 0

Reorder the terms:
12 + 4y + 5y2 = 0

Solving
12 + 4y + 5y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
2.4 + 0.8y + y2 = 0

Move the constant term to the right:

Add '-2.4' to each side of the equation.
2.4 + 0.8y + -2.4 + y2 = 0 + -2.4

Reorder the terms:
2.4 + -2.4 + 0.8y + y2 = 0 + -2.4

Combine like terms: 2.4 + -2.4 = 0.0
0.0 + 0.8y + y2 = 0 + -2.4
0.8y + y2 = 0 + -2.4

Combine like terms: 0 + -2.4 = -2.4
0.8y + y2 = -2.4

The y term is 0.8y.  Take half its coefficient (0.4).
Square it (0.16) and add it to both sides.

Add '0.16' to each side of the equation.
0.8y + 0.16 + y2 = -2.4 + 0.16

Reorder the terms:
0.16 + 0.8y + y2 = -2.4 + 0.16

Combine like terms: -2.4 + 0.16 = -2.24
0.16 + 0.8y + y2 = -2.24

Factor a perfect square on the left side:
(y + 0.4)(y + 0.4) = -2.24

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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